2(4x^2-3)=6(x^2-5)

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Solution for 2(4x^2-3)=6(x^2-5) equation: 



2(4x^2-3)=6(x^2-5)

We move all terms to the left:

2(4x^2-3)-(6(x^2-5))=0

We multiply parentheses

8x^2-(6(x^2-5))-6=0



We calculate terms in parentheses: -(6(x^2-5)), so:

6(x^2-5)

We multiply parentheses

6x^2-30

Back to the equation:

-(6x^2-30)



We get rid of parentheses

8x^2-6x^2+30-6=0

We add all the numbers together, and all the variables

2x^2+24=0

a = 2; b = 0; c = +24;
Δ = b2-4ac
Δ = 02-4·2·24
Δ = -192
Delta is less than zero, so there is no solution for the equation

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